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211255413407 = 853632474789
BaseRepresentation
bin1100010010111111001…
…1011100101010011111
3202012021202022221001122
43010233303130222133
511430122341212112
6241014400401155
721156051246233
oct3045763345237
9665252287048
10211255413407
118165819a955
1234b390161bb
1316bc91331cc
14a320c7a5c3
155766666872
hex312fcdca9f

211255413407 has 4 divisors (see below), whose sum is σ = 211257973560. Its totient is φ = 211252853256.

The previous prime is 211255413401. The next prime is 211255413427. The reversal of 211255413407 is 704314552112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-211255413407 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (211255413401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1152032 + ... + 1322757.

It is an arithmetic number, because the mean of its divisors is an integer number (52814493390).

Almost surely, 2211255413407 is an apocalyptic number.

211255413407 is a deficient number, since it is larger than the sum of its proper divisors (2560153).

211255413407 is an equidigital number, since it uses as much as digits as its factorization.

211255413407 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2560152.

The product of its (nonzero) digits is 33600, while the sum is 35.

Adding to 211255413407 its reverse (704314552112), we get a palindrome (915569965519).

The spelling of 211255413407 in words is "two hundred eleven billion, two hundred fifty-five million, four hundred thirteen thousand, four hundred seven".

Divisors: 1 85363 2474789 211255413407