Base | Representation |
---|---|
bin | 11110101111111000100… |
… | …111011000011001110010 |
3 | 21111000000121022101220101 |
4 | 132233320213120121302 |
5 | 234104411000443344 |
6 | 4254410535303014 |
7 | 305442052534225 |
oct | 36577047303162 |
9 | 7430017271811 |
10 | 2113000015474 |
11 | 745133471a27 |
12 | 2a161b51aa6a |
13 | 12434144c85a |
14 | 743ac2815bc |
15 | 39e6d66d9d4 |
hex | 1ebf89d8672 |
2113000015474 has 4 divisors (see below), whose sum is σ = 3169500023214. Its totient is φ = 1056500007736.
The previous prime is 2113000015459. The next prime is 2113000015507. The reversal of 2113000015474 is 4745100003112.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1980755056449 + 132244959025 = 1407393^2 + 363655^2 .
It is a super-4 number, since 4×21130000154744 (a number of 50 digits) contains 4444 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 528250003867 + ... + 528250003870.
Almost surely, 22113000015474 is an apocalyptic number.
2113000015474 is a deficient number, since it is larger than the sum of its proper divisors (1056500007740).
2113000015474 is a wasteful number, since it uses less digits than its factorization.
2113000015474 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1056500007739.
The product of its (nonzero) digits is 3360, while the sum is 28.
Adding to 2113000015474 its reverse (4745100003112), we get a palindrome (6858100018586).
The spelling of 2113000015474 in words is "two trillion, one hundred thirteen billion, fifteen thousand, four hundred seventy-four".
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