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2113000015474 = 21056500007737
BaseRepresentation
bin11110101111111000100…
…111011000011001110010
321111000000121022101220101
4132233320213120121302
5234104411000443344
64254410535303014
7305442052534225
oct36577047303162
97430017271811
102113000015474
11745133471a27
122a161b51aa6a
1312434144c85a
14743ac2815bc
1539e6d66d9d4
hex1ebf89d8672

2113000015474 has 4 divisors (see below), whose sum is σ = 3169500023214. Its totient is φ = 1056500007736.

The previous prime is 2113000015459. The next prime is 2113000015507. The reversal of 2113000015474 is 4745100003112.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1980755056449 + 132244959025 = 1407393^2 + 363655^2 .

It is a super-4 number, since 4×21130000154744 (a number of 50 digits) contains 4444 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 528250003867 + ... + 528250003870.

Almost surely, 22113000015474 is an apocalyptic number.

2113000015474 is a deficient number, since it is larger than the sum of its proper divisors (1056500007740).

2113000015474 is a wasteful number, since it uses less digits than its factorization.

2113000015474 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1056500007739.

The product of its (nonzero) digits is 3360, while the sum is 28.

Adding to 2113000015474 its reverse (4745100003112), we get a palindrome (6858100018586).

The spelling of 2113000015474 in words is "two trillion, one hundred thirteen billion, fifteen thousand, four hundred seventy-four".

Divisors: 1 2 1056500007737 2113000015474