Base | Representation |
---|---|
bin | 11110101111111000101… |
… | …011100001010000101011 |
3 | 21111000000200100112001021 |
4 | 132233320223201100223 |
5 | 234104411240202311 |
6 | 4254411014433311 |
7 | 305442065003122 |
oct | 36577053412053 |
9 | 7430020315037 |
10 | 2113001100331 |
11 | 745134043000 |
12 | 2a161b962837 |
13 | 12434173c594 |
14 | 743ac484ab9 |
15 | 39e6d7d5171 |
hex | 1ebf8ae142b |
2113001100331 has 32 divisors (see below), whose sum is σ = 2333646685440. Its totient is φ = 1913071216320.
The previous prime is 2113001100247. The next prime is 2113001100367. The reversal of 2113001100331 is 1330011003112.
It is not a de Polignac number, because 2113001100331 - 235 = 2078641361963 is a prime.
It is a super-2 number, since 2×21130011003312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2113001110331) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 371808016 + ... + 371813698.
It is an arithmetic number, because the mean of its divisors is an integer number (72926458920).
Almost surely, 22113001100331 is an apocalyptic number.
2113001100331 is a deficient number, since it is larger than the sum of its proper divisors (220645585109).
2113001100331 is an equidigital number, since it uses as much as digits as its factorization.
2113001100331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6808 (or 6786 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 2113001100331 its reverse (1330011003112), we get a palindrome (3443012103443).
The spelling of 2113001100331 in words is "two trillion, one hundred thirteen billion, one million, one hundred thousand, three hundred thirty-one".
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