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21130220013 = 371006200953
BaseRepresentation
bin10011101011011101…
…011001000111101101
32000112121020101122020
4103223131121013231
5321233314020023
613412421540353
71345424622660
oct235335310755
960477211566
1021130220013
118a63505051
1241185746b9
131cb98a9786
14104644d6d7
1583a0c0de3
hex4eb7591ed

21130220013 has 8 divisors (see below), whose sum is σ = 32198430528. Its totient is φ = 12074411424.

The previous prime is 21130219997. The next prime is 21130220021. The reversal of 21130220013 is 31002203112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 21130220013 - 24 = 21130219997 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 21130219974 and 21130220001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21130220513) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 503100456 + ... + 503100497.

It is an arithmetic number, because the mean of its divisors is an integer number (4024803816).

Almost surely, 221130220013 is an apocalyptic number.

It is an amenable number.

21130220013 is a deficient number, since it is larger than the sum of its proper divisors (11068210515).

21130220013 is a wasteful number, since it uses less digits than its factorization.

21130220013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1006200963.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 21130220013 its reverse (31002203112), we get a palindrome (52132423125).

The spelling of 21130220013 in words is "twenty-one billion, one hundred thirty million, two hundred twenty thousand, thirteen".

Divisors: 1 3 7 21 1006200953 3018602859 7043406671 21130220013