Base | Representation |
---|---|
bin | 110000000010111110110100… |
… | …011011001011100011100010 |
3 | 1000201012010221111010201120201 |
4 | 300002332310123023203202 |
5 | 210144110134443120002 |
6 | 2025230553443055414 |
7 | 62336503421526325 |
oct | 6002766433134342 |
9 | 1021163844121521 |
10 | 211311123020002 |
11 | 6136a5a9091075 |
12 | 1b84961767156a |
13 | 90ba726a7c875 |
14 | 3a277276727bc |
15 | 1966a49697087 |
hex | c02fb46cb8e2 |
211311123020002 has 4 divisors (see below), whose sum is σ = 316966684530006. Its totient is φ = 105655561510000.
The previous prime is 211311123019979. The next prime is 211311123020003. The reversal of 211311123020002 is 200020321113112.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 203327893157481 + 7983229862521 = 14259309^2 + 2825461^2 .
It is not an unprimeable number, because it can be changed into a prime (211311123020003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52827780754999 + ... + 52827780755002.
Almost surely, 2211311123020002 is an apocalyptic number.
211311123020002 is a deficient number, since it is larger than the sum of its proper divisors (105655561510004).
211311123020002 is a wasteful number, since it uses less digits than its factorization.
211311123020002 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 105655561510003.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 211311123020002 its reverse (200020321113112), we get a palindrome (411331444133114).
The spelling of 211311123020002 in words is "two hundred eleven trillion, three hundred eleven billion, one hundred twenty-three million, twenty thousand, two".
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