Search a number
-
+
211311214303 = 749996038671
BaseRepresentation
bin1100010011001100100…
…0010011111011011111
3202012102122022220111111
43010303020103323133
511430231132324203
6241024112402451
721160326454120
oct3046310237337
9665378286444
10211311214303
11816867429a2
1234b53846427
1316c0786caa7
14a328444047
15576b4da26d
hex3133213edf

211311214303 has 8 divisors (see below), whose sum is σ = 241546880000. Its totient is φ = 181087635960.

The previous prime is 211311214291. The next prime is 211311214343. The reversal of 211311214303 is 303412113112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 211311214303 - 25 = 211311214271 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (211311214343) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2984343 + ... + 3054328.

It is an arithmetic number, because the mean of its divisors is an integer number (30193360000).

Almost surely, 2211311214303 is an apocalyptic number.

211311214303 is a deficient number, since it is larger than the sum of its proper divisors (30235665697).

211311214303 is an equidigital number, since it uses as much as digits as its factorization.

211311214303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6043677.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 211311214303 its reverse (303412113112), we get a palindrome (514723327415).

The spelling of 211311214303 in words is "two hundred eleven billion, three hundred eleven million, two hundred fourteen thousand, three hundred three".

Divisors: 1 7 4999 34993 6038671 42270697 30187316329 211311214303