Base | Representation |
---|---|
bin | 111110111110011… |
… | …1010101101011001 |
3 | 12110021012200012221 |
4 | 1331330322231121 |
5 | 13311424333423 |
6 | 545403304041 |
7 | 103236142645 |
oct | 17574725531 |
9 | 5407180187 |
10 | 2113121113 |
11 | 994890194 |
12 | 4ab81b021 |
13 | 278a3322c |
14 | 160903c25 |
15 | c57a9e5d |
hex | 7df3ab59 |
2113121113 has 4 divisors (see below), whose sum is σ = 2204995968. Its totient is φ = 2021246260.
The previous prime is 2113121111. The next prime is 2113121137. The reversal of 2113121113 is 3111213112.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2113121113 - 21 = 2113121111 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2113121111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45937393 + ... + 45937438.
It is an arithmetic number, because the mean of its divisors is an integer number (551248992).
Almost surely, 22113121113 is an apocalyptic number.
2113121113 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
It is an amenable number.
2113121113 is a deficient number, since it is larger than the sum of its proper divisors (91874855).
2113121113 is an equidigital number, since it uses as much as digits as its factorization.
2113121113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 91874854.
The product of its digits is 36, while the sum is 16.
The square root of 2113121113 is about 45968.6970992218. The cubic root of 2113121113 is about 1283.2407125749.
Adding to 2113121113 its reverse (3111213112), we get a palindrome (5224334225).
The spelling of 2113121113 in words is "two billion, one hundred thirteen million, one hundred twenty-one thousand, one hundred thirteen".
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