Base | Representation |
---|---|
bin | 1100010011001100101… |
… | …1110011110000111101 |
3 | 202012102201001111011011 |
4 | 3010303023303300331 |
5 | 11430231401144013 |
6 | 241024144155221 |
7 | 21160340323105 |
oct | 3046313636075 |
9 | 665381044134 |
10 | 211312131133 |
11 | 81687209804 |
12 | 34b54008b11 |
13 | 16c07b011ac |
14 | a328602205 |
15 | 576b61bc3d |
hex | 31332f3c3d |
211312131133 has 4 divisors (see below), whose sum is σ = 211602795040. Its totient is φ = 211021467228.
The previous prime is 211312131131. The next prime is 211312131229. The reversal of 211312131133 is 331131213112.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 211312131133 - 21 = 211312131131 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (211312131131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 145330863 + ... + 145332316.
It is an arithmetic number, because the mean of its divisors is an integer number (52900698760).
Almost surely, 2211312131133 is an apocalyptic number.
It is an amenable number.
211312131133 is a deficient number, since it is larger than the sum of its proper divisors (290663907).
211312131133 is an equidigital number, since it uses as much as digits as its factorization.
211312131133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 290663906.
The product of its digits is 324, while the sum is 22.
Adding to 211312131133 its reverse (331131213112), we get a palindrome (542443344245).
The spelling of 211312131133 in words is "two hundred eleven billion, three hundred twelve million, one hundred thirty-one thousand, one hundred thirty-three".
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