Base | Representation |
---|---|
bin | 1001100110111111111110… |
… | …00111101011010000100111 |
3 | 2202211010101100121122120102 |
4 | 10303133333013223100213 |
5 | 10232203221412100203 |
6 | 112535314521254315 |
7 | 4310452303132202 |
oct | 463377707532047 |
9 | 82733340548512 |
10 | 21131224331303 |
11 | 680777a277309 |
12 | 245345833439b |
13 | ba3886cb7298 |
14 | 530a845d4939 |
15 | 269a11ba5888 |
hex | 1337ff1eb427 |
21131224331303 has 8 divisors (see below), whose sum is σ = 22384081051488. Its totient is φ = 19879461336064.
The previous prime is 21131224331299. The next prime is 21131224331309. The reversal of 21131224331303 is 30313342213112.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 21131224331303 - 22 = 21131224331299 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21131224331309) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 273391451 + ... + 273468732.
It is an arithmetic number, because the mean of its divisors is an integer number (2798010131436).
Almost surely, 221131224331303 is an apocalyptic number.
21131224331303 is a deficient number, since it is larger than the sum of its proper divisors (1252856720185).
21131224331303 is a wasteful number, since it uses less digits than its factorization.
21131224331303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 546862473.
The product of its (nonzero) digits is 7776, while the sum is 29.
Adding to 21131224331303 its reverse (30313342213112), we get a palindrome (51444566544415).
The spelling of 21131224331303 in words is "twenty-one trillion, one hundred thirty-one billion, two hundred twenty-four million, three hundred thirty-one thousand, three hundred three".
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