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2113131222103 = 11192102838373
BaseRepresentation
bin11110110000000000011…
…011111001010001010111
321111000100202012101120011
4132300000123321101113
5234110143043101403
64254431543421051
7305445235011646
oct36600033712127
97430322171504
102113131222103
117451a0538460
122a1657454787
1312436269b605
14743c187735d
1539e79e39a6d
hex1ec006f9457

2113131222103 has 4 divisors (see below), whose sum is σ = 2305234060488. Its totient is φ = 1921028383720.

The previous prime is 2113131222077. The next prime is 2113131222113. The reversal of 2113131222103 is 3012221313112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2113131222103 - 225 = 2113097667671 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2113131222113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 96051419176 + ... + 96051419197.

It is an arithmetic number, because the mean of its divisors is an integer number (576308515122).

Almost surely, 22113131222103 is an apocalyptic number.

2113131222103 is a deficient number, since it is larger than the sum of its proper divisors (192102838385).

2113131222103 is a wasteful number, since it uses less digits than its factorization.

2113131222103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 192102838384.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 2113131222103 its reverse (3012221313112), we get a palindrome (5125352535215).

The spelling of 2113131222103 in words is "two trillion, one hundred thirteen billion, one hundred thirty-one million, two hundred twenty-two thousand, one hundred three".

Divisors: 1 11 192102838373 2113131222103