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2113140211111 = 13715424381103
BaseRepresentation
bin11110110000000000111…
…110001011110110100111
321111000101101010002011101
4132300000332023312213
5234110202343223421
64254432504220531
7305445404300656
oct36600076136647
97430341102141
102113140211111
117451a5617a96
122a165a46a747
131243644c7c57
14743c2b3719d
1539e7ab13191
hex1ec00f8bda7

2113140211111 has 4 divisors (see below), whose sum is σ = 2128564592352. Its totient is φ = 2097715829872.

The previous prime is 2113140211009. The next prime is 2113140211141. The reversal of 2113140211111 is 1111120413112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2113140211111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2113140211141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7712190415 + ... + 7712190688.

It is an arithmetic number, because the mean of its divisors is an integer number (532141148088).

Almost surely, 22113140211111 is an apocalyptic number.

2113140211111 is a deficient number, since it is larger than the sum of its proper divisors (15424381241).

2113140211111 is a wasteful number, since it uses less digits than its factorization.

2113140211111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15424381240.

The product of its (nonzero) digits is 48, while the sum is 19.

Adding to 2113140211111 its reverse (1111120413112), we get a palindrome (3224260624223).

The spelling of 2113140211111 in words is "two trillion, one hundred thirteen billion, one hundred forty million, two hundred eleven thousand, one hundred eleven".

Divisors: 1 137 15424381103 2113140211111