Base | Representation |
---|---|
bin | 1100010011001111010… |
… | …1101100001011100010 |
3 | 202012110110201021111002 |
4 | 3010303311230023202 |
5 | 11430242204010424 |
6 | 241025215352002 |
7 | 21160532540564 |
oct | 3046365541342 |
9 | 665413637432 |
10 | 211323110114 |
11 | 81692428446 |
12 | 34b57822602 |
13 | 16c0a17652c |
14 | a329c5d334 |
15 | 576c589cae |
hex | 3133d6c2e2 |
211323110114 has 4 divisors (see below), whose sum is σ = 316984665174. Its totient is φ = 105661555056.
The previous prime is 211323110101. The next prime is 211323110177. The reversal of 211323110114 is 411011323112.
211323110114 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 197550914089 + 13772196025 = 444467^2 + 117355^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52830777527 + ... + 52830777530.
Almost surely, 2211323110114 is an apocalyptic number.
211323110114 is a deficient number, since it is larger than the sum of its proper divisors (105661555060).
211323110114 is a wasteful number, since it uses less digits than its factorization.
211323110114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 105661555059.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 211323110114 its reverse (411011323112), we get a palindrome (622334433226).
The spelling of 211323110114 in words is "two hundred eleven billion, three hundred twenty-three million, one hundred ten thousand, one hundred fourteen".
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