Base | Representation |
---|---|
bin | 110000000011001010000110… |
… | …010000010011110001101001 |
3 | 1000201020022012110210201010210 |
4 | 300003022012100103301221 |
5 | 210144304440212220131 |
6 | 2025240315252531333 |
7 | 62340412502424453 |
oct | 6003120620236151 |
9 | 1021208173721123 |
10 | 211323233320041 |
11 | 613747530297a7 |
12 | 1b84ba37320b49 |
13 | 90bb906a2318b |
14 | 3a28155ba32d3 |
15 | 1967007954146 |
hex | c03286413c69 |
211323233320041 has 16 divisors (see below), whose sum is σ = 283657760483328. Its totient is φ = 139935611514000.
The previous prime is 211323233320021. The next prime is 211323233320127. The reversal of 211323233320041 is 140023332323112.
It is not a de Polignac number, because 211323233320041 - 213 = 211323233311849 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 211323233319990 and 211323233320008.
It is not an unprimeable number, because it can be changed into a prime (211323233320021) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17897601 + ... + 27257486.
It is an arithmetic number, because the mean of its divisors is an integer number (17728610030208).
Almost surely, 2211323233320041 is an apocalyptic number.
It is an amenable number.
211323233320041 is a deficient number, since it is larger than the sum of its proper divisors (72334527163287).
211323233320041 is a wasteful number, since it uses less digits than its factorization.
211323233320041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 45165572.
The product of its (nonzero) digits is 15552, while the sum is 30.
Adding to 211323233320041 its reverse (140023332323112), we get a palindrome (351346565643153).
The spelling of 211323233320041 in words is "two hundred eleven trillion, three hundred twenty-three billion, two hundred thirty-three million, three hundred twenty thousand, forty-one".
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