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2113233120535 = 5422646624107
BaseRepresentation
bin11110110000000110100…
…000100110110100010111
321111000121211221100221011
4132300012200212310113
5234110400134324120
64254450023433051
7305450613101635
oct36600640466427
97430554840834
102113233120535
11745243006239
122a16855b5787
1312437a828244
14743d1200355
1539e83d66c5a
hex1ec06826d17

2113233120535 has 4 divisors (see below), whose sum is σ = 2535879744648. Its totient is φ = 1690586496424.

The previous prime is 2113233120469. The next prime is 2113233120541. The reversal of 2113233120535 is 5350213323112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2113233120535 - 27 = 2113233120407 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2113233120497 and 2113233120506.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 211323312049 + ... + 211323312058.

It is an arithmetic number, because the mean of its divisors is an integer number (633969936162).

Almost surely, 22113233120535 is an apocalyptic number.

2113233120535 is a deficient number, since it is larger than the sum of its proper divisors (422646624113).

2113233120535 is an equidigital number, since it uses as much as digits as its factorization.

2113233120535 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 422646624112.

The product of its (nonzero) digits is 16200, while the sum is 31.

Adding to 2113233120535 its reverse (5350213323112), we get a palindrome (7463446443647).

The spelling of 2113233120535 in words is "two trillion, one hundred thirteen billion, two hundred thirty-three million, one hundred twenty thousand, five hundred thirty-five".

Divisors: 1 5 422646624107 2113233120535