Base | Representation |
---|---|
bin | 1100010011001111111… |
… | …0001111000010010011 |
3 | 202012110121221002002010 |
4 | 3010303332033002103 |
5 | 11430243242200120 |
6 | 241025335354003 |
7 | 21160560560142 |
oct | 3046376170223 |
9 | 665417832063 |
10 | 211325350035 |
11 | 81693718318 |
12 | 34b58522903 |
13 | 16c0a77bc27 |
14 | a32a283759 |
15 | 576c87d7e0 |
hex | 3133f8f093 |
211325350035 has 16 divisors (see below), whose sum is σ = 338447903904. Its totient is φ = 112597738752.
The previous prime is 211325350007. The next prime is 211325350037. The reversal of 211325350035 is 530053523112.
It is not a de Polignac number, because 211325350035 - 25 = 211325350003 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 211325349984 and 211325350011.
It is not an unprimeable number, because it can be changed into a prime (211325350037) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6803652 + ... + 6834641.
It is an arithmetic number, because the mean of its divisors is an integer number (21152993994).
Almost surely, 2211325350035 is an apocalyptic number.
211325350035 is a deficient number, since it is larger than the sum of its proper divisors (127122553869).
211325350035 is a wasteful number, since it uses less digits than its factorization.
211325350035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13639334.
The product of its (nonzero) digits is 13500, while the sum is 30.
Adding to 211325350035 its reverse (530053523112), we get a palindrome (741378873147).
The spelling of 211325350035 in words is "two hundred eleven billion, three hundred twenty-five million, three hundred fifty thousand, thirty-five".
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