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2113311012103 = 96719511120159
BaseRepresentation
bin11110110000001011001…
…001101111010100000111
321111000211021111200002001
4132300023021233110013
5234111030104341403
64254501445130131
7305452550134024
oct36601311572407
97430737450061
102113311012103
11745282a77335
122a16a76b9947
131243909caa25
14743db6b854b
1539e8ab00c1d
hex1ec0b26f507

2113311012103 has 8 divisors (see below), whose sum is σ = 2116582645760. Its totient is φ = 2110041624600.

The previous prime is 2113311012083. The next prime is 2113311012173. The reversal of 2113311012103 is 3012101133112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2113311012103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2113311012173) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1326538 + ... + 2446696.

It is an arithmetic number, because the mean of its divisors is an integer number (264572830720).

Almost surely, 22113311012103 is an apocalyptic number.

2113311012103 is a deficient number, since it is larger than the sum of its proper divisors (3271633657).

2113311012103 is a wasteful number, since it uses less digits than its factorization.

2113311012103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1123077.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 2113311012103 its reverse (3012101133112), we get a palindrome (5125412145215).

The spelling of 2113311012103 in words is "two trillion, one hundred thirteen billion, three hundred eleven million, twelve thousand, one hundred three".

Divisors: 1 967 1951 1120159 1886617 1083193753 2185430209 2113311012103