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211332431113 = 347609027179
BaseRepresentation
bin1100010011010001100…
…1001111110100001001
3202012111010020211111021
43010310121033310021
511430302100243423
6241030151232441
721161005011526
oct3046431176411
9665433224437
10211332431113
1181697714451
1234b5a978721
1316c0c08b00b
14a32b1a814d
15576d2cb95d
hex313464fd09

211332431113 has 4 divisors (see below), whose sum is σ = 211941458640. Its totient is φ = 210723403588.

The previous prime is 211332431077. The next prime is 211332431117. The reversal of 211332431113 is 311134233112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 211332431113 - 213 = 211332422921 is a prime.

It is a super-2 number, since 2×2113324311132 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (211332431117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 304513243 + ... + 304513936.

It is an arithmetic number, because the mean of its divisors is an integer number (52985364660).

Almost surely, 2211332431113 is an apocalyptic number.

It is an amenable number.

211332431113 is a deficient number, since it is larger than the sum of its proper divisors (609027527).

211332431113 is an equidigital number, since it uses as much as digits as its factorization.

211332431113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 609027526.

The product of its digits is 1296, while the sum is 25.

Adding to 211332431113 its reverse (311134233112), we get a palindrome (522466664225).

The spelling of 211332431113 in words is "two hundred eleven billion, three hundred thirty-two million, four hundred thirty-one thousand, one hundred thirteen".

Divisors: 1 347 609027179 211332431113