Base | Representation |
---|---|
bin | 11110110000001100010… |
… | …011110101000000111111 |
3 | 21111000212122001102001200 |
4 | 132300030103311000333 |
5 | 234111100042342421 |
6 | 4254503421310543 |
7 | 305453204204661 |
oct | 36601423650077 |
9 | 7430778042050 |
10 | 2113330434111 |
11 | 745292a32386 |
12 | 2a16b2105453 |
13 | 124394a3b040 |
14 | 744000d2531 |
15 | 39e8c68a726 |
hex | 1ec0c4f503f |
2113330434111 has 12 divisors (see below), whose sum is σ = 3287402897688. Its totient is φ = 1300511036304.
The previous prime is 2113330434109. The next prime is 2113330434151. The reversal of 2113330434111 is 1114340333112.
2113330434111 is a `hidden beast` number, since 2 + 1 + 1 + 3 + 3 + 304 + 341 + 11 = 666.
It is not a de Polignac number, because 2113330434111 - 21 = 2113330434109 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2113330434151) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 9031326525 + ... + 9031326758.
It is an arithmetic number, because the mean of its divisors is an integer number (273950241474).
Almost surely, 22113330434111 is an apocalyptic number.
2113330434111 is a deficient number, since it is larger than the sum of its proper divisors (1174072463577).
2113330434111 is a wasteful number, since it uses less digits than its factorization.
2113330434111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18062653302 (or 18062653299 counting only the distinct ones).
The product of its (nonzero) digits is 2592, while the sum is 27.
Adding to 2113330434111 its reverse (1114340333112), we get a palindrome (3227670767223).
The spelling of 2113330434111 in words is "two trillion, one hundred thirteen billion, three hundred thirty million, four hundred thirty-four thousand, one hundred eleven".
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