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2113333400111 = 2817520759431
BaseRepresentation
bin11110110000001100011…
…111001001001000101111
321111000212211122002122112
4132300030133021020233
5234111101322300421
64254504005034235
7305453241340133
oct36601437111057
97430784562575
102113333400111
1174529467881a
122a16b30b597b
1312439553907b
14744006653c3
1539e8ca7445b
hex1ec0c7c922f

2113333400111 has 4 divisors (see below), whose sum is σ = 2120854159824. Its totient is φ = 2105812640400.

The previous prime is 2113333400083. The next prime is 2113333400131. The reversal of 2113333400111 is 1110043333112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2113333400111 - 26 = 2113333400047 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2113333400131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3760379435 + ... + 3760379996.

It is an arithmetic number, because the mean of its divisors is an integer number (530213539956).

Almost surely, 22113333400111 is an apocalyptic number.

2113333400111 is a deficient number, since it is larger than the sum of its proper divisors (7520759713).

2113333400111 is an equidigital number, since it uses as much as digits as its factorization.

2113333400111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7520759712.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 2113333400111 its reverse (1110043333112), we get a palindrome (3223376733223).

The spelling of 2113333400111 in words is "two trillion, one hundred thirteen billion, three hundred thirty-three million, four hundred thousand, one hundred eleven".

Divisors: 1 281 7520759431 2113333400111