Base | Representation |
---|---|
bin | 11110110000010000100… |
… | …101010001000000110111 |
3 | 21111001001121221010112012 |
4 | 132300100211101000313 |
5 | 234111221420122403 |
6 | 4254514501514435 |
7 | 305455034366360 |
oct | 36602045210067 |
9 | 7431047833465 |
10 | 2113402114103 |
11 | 74531a440645 |
12 | 2a1712112a1b |
13 | 1243a6847437 |
14 | 74409830b67 |
15 | 39e93ae8ed8 |
hex | 1ec10951037 |
2113402114103 has 4 divisors (see below), whose sum is σ = 2415316701840. Its totient is φ = 1811487526368.
The previous prime is 2113402114099. The next prime is 2113402114121. The reversal of 2113402114103 is 3014112043112.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2113402114103 - 22 = 2113402114099 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2113402114133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 150957293858 + ... + 150957293871.
It is an arithmetic number, because the mean of its divisors is an integer number (603829175460).
Almost surely, 22113402114103 is an apocalyptic number.
2113402114103 is a deficient number, since it is larger than the sum of its proper divisors (301914587737).
2113402114103 is an equidigital number, since it uses as much as digits as its factorization.
2113402114103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 301914587736.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 2113402114103 its reverse (3014112043112), we get a palindrome (5127514157215).
The spelling of 2113402114103 in words is "two trillion, one hundred thirteen billion, four hundred two million, one hundred fourteen thousand, one hundred three".
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