2113402412131 has 4 divisors (see below), whose sum is σ = 2205289473552. Its totient is φ = 2021515350712.

The previous prime is 2113402412111. The next prime is 2113402412141. The reversal of 2113402412131 is 1312142043112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2113402412131 is a prime.

It is a super-2 number, since 2×2113402412131² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2113402412096 and 2113402412105.

It is not an unprimeable number, because it can be changed into a prime (2113402412111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45943530676 + ... + 45943530721.

It is an arithmetic number, because the mean of its divisors is an integer number (551322368388).

Almost surely, 2^{2113402412131} is an apocalyptic number.

2113402412131 is a deficient number, since it is larger than the sum of its proper divisors (91887061421).

2113402412131 is an equidigital number, since it uses as much as digits as its factorization.

2113402412131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 91887061420.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 2113402412131 its reverse (1312142043112), we get a palindrome (3425544455243).

The spelling of 2113402412131 in words is "two trillion, one hundred thirteen billion, four hundred two million, four hundred twelve thousand, one hundred thirty-one".