211342303243111 has 4 divisors (see below), whose sum is σ = 211362071498424. Its totient is φ = 211322534987800.

The previous prime is 211342303243067. The next prime is 211342303243139. The reversal of 211342303243111 is 111342303243112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 211342303243111 - 2²¹ = 211342301145959 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (211342303243151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9884111620 + ... + 9884133001.

It is an arithmetic number, because the mean of its divisors is an integer number (52840517874606).

Almost surely, 2^{211342303243111} is an apocalyptic number.

211342303243111 is a deficient number, since it is larger than the sum of its proper divisors (19768255313).

211342303243111 is a wasteful number, since it uses less digits than its factorization.

211342303243111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19768255312.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 211342303243111 its reverse (111342303243112), we get a palindrome (322684606486223).

Subtracting from 211342303243111 its reverse (111342303243112), we obtain a palindrome (99999999999999).

The spelling of 211342303243111 in words is "two hundred eleven trillion, three hundred forty-two billion, three hundred three million, two hundred forty-three thousand, one hundred eleven".