Base | Representation |
---|---|
bin | 1001100111000101101100… |
… | …11110000001110100111011 |
3 | 2202211102022201211012221120 |
4 | 10303202312132001310323 |
5 | 10232231021401441220 |
6 | 112540544044440323 |
7 | 4310621444355045 |
oct | 463426636016473 |
9 | 82742281735846 |
10 | 21134300421435 |
11 | 6809008688363 |
12 | 2453b765490a3 |
13 | ba3c57390366 |
14 | 530c96d66a95 |
15 | 269b41c79a40 |
hex | 1338b6781d3b |
21134300421435 has 32 divisors (see below), whose sum is σ = 34382481457728. Its totient is φ = 11082569195520.
The previous prime is 21134300421427. The next prime is 21134300421461. The reversal of 21134300421435 is 53412400343112.
It is not a de Polignac number, because 21134300421435 - 23 = 21134300421427 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 21134300421396 and 21134300421405.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2081242 + ... + 6826431.
It is an arithmetic number, because the mean of its divisors is an integer number (1074452545554).
Almost surely, 221134300421435 is an apocalyptic number.
21134300421435 is a deficient number, since it is larger than the sum of its proper divisors (13248181036293).
21134300421435 is a wasteful number, since it uses less digits than its factorization.
21134300421435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8910335.
The product of its (nonzero) digits is 34560, while the sum is 33.
Adding to 21134300421435 its reverse (53412400343112), we get a palindrome (74546700764547).
The spelling of 21134300421435 in words is "twenty-one trillion, one hundred thirty-four billion, three hundred million, four hundred twenty-one thousand, four hundred thirty-five".
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