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2113524115 = 5422704823
BaseRepresentation
bin111110111111001…
…1101000110010011
312110021222011000221
41331332131012103
513312030232430
6545420053511
7103242441613
oct17576350623
95407864027
102113524115
11995035a4a
124ab994297
13278b447b1
141609aaa43
15c583957a
hex7df9d193

2113524115 has 4 divisors (see below), whose sum is σ = 2536228944. Its totient is φ = 1690819288.

The previous prime is 2113524103. The next prime is 2113524121. The reversal of 2113524115 is 5114253112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2113524115 - 29 = 2113523603 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 2113524115.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 211352407 + ... + 211352416.

It is an arithmetic number, because the mean of its divisors is an integer number (634057236).

Almost surely, 22113524115 is an apocalyptic number.

2113524115 is a deficient number, since it is larger than the sum of its proper divisors (422704829).

2113524115 is an equidigital number, since it uses as much as digits as its factorization.

2113524115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 422704828.

The product of its digits is 1200, while the sum is 25.

The square root of 2113524115 is about 45973.0803296886. The cubic root of 2113524115 is about 1283.3222847571.

Adding to 2113524115 its reverse (5114253112), we get a palindrome (7227777227).

The spelling of 2113524115 in words is "two billion, one hundred thirteen million, five hundred twenty-four thousand, one hundred fifteen".

Divisors: 1 5 422704823 2113524115