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2114040000001 = 13211600333081
BaseRepresentation
bin11110110000110110100…
…110100110111000000001
321111002201002020002110211
4132300312212212320001
5234114023220000001
64255102045554121
7305506611340126
oct36606646467001
97432632202424
102114040000001
11745617515776
122a186b875941
13124478a49507
147446a43a74d
1539eceaec351
hex1ec369a6e01

2114040000001 has 4 divisors (see below), whose sum is σ = 2115640334404. Its totient is φ = 2112439665600.

The previous prime is 2114039999977. The next prime is 2114040000031. The reversal of 2114040000001 is 1000000404112.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1895787519376 + 218252480625 = 1376876^2 + 467175^2 .

It is a cyclic number.

It is not a de Polignac number, because 2114040000001 - 217 = 2114039868929 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2114040000031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 800165220 + ... + 800167861.

It is an arithmetic number, because the mean of its divisors is an integer number (528910083601).

Almost surely, 22114040000001 is an apocalyptic number.

It is an amenable number.

2114040000001 is a deficient number, since it is larger than the sum of its proper divisors (1600334403).

2114040000001 is a wasteful number, since it uses less digits than its factorization.

2114040000001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1600334402.

The product of its (nonzero) digits is 32, while the sum is 13.

Adding to 2114040000001 its reverse (1000000404112), we get a palindrome (3114040404113).

The spelling of 2114040000001 in words is "two trillion, one hundred fourteen billion, forty million, one", and thus it is an aban number.

Divisors: 1 1321 1600333081 2114040000001