Search a number
-
+
21140400000011 = 31167975562701
BaseRepresentation
bin1001100111010001000100…
…00010000100110000001011
32202212000001211020220202012
410303220202002010300023
510232331014400000021
6112543433215530135
74311225551052005
oct463504202046013
982760054226665
1021140400000011
116810658741a96
12245519922994b
13ba46b9c82b56
145312b5097375
15269d9c4d235b
hex133a22084c0b

21140400000011 has 4 divisors (see below), whose sum is σ = 21208375563024. Its totient is φ = 21072424437000.

The previous prime is 21140399999993. The next prime is 21140400000017. The reversal of 21140400000011 is 11000000404112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21140400000011 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21140400000017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33987781040 + ... + 33987781661.

It is an arithmetic number, because the mean of its divisors is an integer number (5302093890756).

Almost surely, 221140400000011 is an apocalyptic number.

21140400000011 is a deficient number, since it is larger than the sum of its proper divisors (67975563013).

21140400000011 is an equidigital number, since it uses as much as digits as its factorization.

21140400000011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 67975563012.

The product of its (nonzero) digits is 32, while the sum is 14.

Adding to 21140400000011 its reverse (11000000404112), we get a palindrome (32140400404123).

The spelling of 21140400000011 in words is "twenty-one trillion, one hundred forty billion, four hundred million, eleven", and thus it is an aban number.

Divisors: 1 311 67975562701 21140400000011