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2114054147 = 3463610469
BaseRepresentation
bin111111000000001…
…1110100000000011
312110022222002002202
41332000132200003
513312144213042
6545435303415
7103250110112
oct17600364003
95408862082
102114054147
11995368197
124abbaab6b
13278c9bb1a
14160aa7c79
15c58e1632
hex7e01e803

2114054147 has 4 divisors (see below), whose sum is σ = 2114668080. Its totient is φ = 2113440216.

The previous prime is 2114054143. The next prime is 2114054191. The reversal of 2114054147 is 7414504112.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2114054147 - 22 = 2114054143 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2114054143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 301772 + ... + 308697.

It is an arithmetic number, because the mean of its divisors is an integer number (528667020).

Almost surely, 22114054147 is an apocalyptic number.

2114054147 is a deficient number, since it is larger than the sum of its proper divisors (613933).

2114054147 is an equidigital number, since it uses as much as digits as its factorization.

2114054147 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 613932.

The product of its (nonzero) digits is 4480, while the sum is 29.

The square root of 2114054147 is about 45978.8445592101. The cubic root of 2114054147 is about 1283.4295534684.

Adding to 2114054147 its reverse (7414504112), we get a palindrome (9528558259).

The spelling of 2114054147 in words is "two billion, one hundred fourteen million, fifty-four thousand, one hundred forty-seven".

Divisors: 1 3463 610469 2114054147