2114104335543 has 12 divisors (see below), whose sum is σ = 3053992034808. Its totient is φ = 1409270995440.

The previous prime is 2114104335521. The next prime is 2114104335593. The reversal of 2114104335543 is 3455334014112.

2114104335543 is a `hidden beast` number, since 2 + 1 + 1 + 4 + 104 + 3 + 3 + 5 + 543 = 666.

It is not a de Polignac number, because 2114104335543 - 2¹² = 2114104331447 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2114104335498 and 2114104335507.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2114104335593) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 10889680 + ... + 11082117.

It is an arithmetic number, because the mean of its divisors is an integer number (254499336234).

Almost surely, 2^{2114104335543} is an apocalyptic number.

2114104335543 is a deficient number, since it is larger than the sum of its proper divisors (939887699265).

2114104335543 is a wasteful number, since it uses less digits than its factorization.

2114104335543 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21982494 (or 21982491 counting only the distinct ones).

The product of its (nonzero) digits is 86400, while the sum is 36.

Adding to 2114104335543 its reverse (3455334014112), we get a palindrome (5569438349655).

The spelling of 2114104335543 in words is "two trillion, one hundred fourteen billion, one hundred four million, three hundred thirty-five thousand, five hundred forty-three".