2114104430041 has 4 divisors (see below), whose sum is σ = 2114147621392. Its totient is φ = 2114061238692.

The previous prime is 2114104429981. The next prime is 2114104430077. The reversal of 2114104430041 is 1400344014112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2114104430041 is a prime.

It is a super-2 number, since 2×2114104430041² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2114104429988 and 2114104430015.

It is not an unprimeable number, because it can be changed into a prime (2114107430041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21522171 + ... + 21620176.

It is an arithmetic number, because the mean of its divisors is an integer number (528536905348).

Almost surely, 2^{2114104430041} is an apocalyptic number.

It is an amenable number.

2114104430041 is a deficient number, since it is larger than the sum of its proper divisors (43191351).

2114104430041 is an equidigital number, since it uses as much as digits as its factorization.

2114104430041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43191350.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 2114104430041 its reverse (1400344014112), we get a palindrome (3514448444153).

The spelling of 2114104430041 in words is "two trillion, one hundred fourteen billion, one hundred four million, four hundred thirty thousand, forty-one".