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21141044303 = 59935293897
BaseRepresentation
bin10011101100000110…
…101011110001001111
32000120100121022202212
4103230012223301033
5321244101404203
613413445541035
71345615624451
oct235406536117
960510538685
1021141044303
118a69628545
12412011477b
131cbbbc9592
141047a6a2d1
1583b00d1d8
hex4ec1abc4f

21141044303 has 4 divisors (see below), whose sum is σ = 21176338800. Its totient is φ = 21105749808.

The previous prime is 21141044261. The next prime is 21141044311. The reversal of 21141044303 is 30344014112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 21141044303 - 28 = 21141044047 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21141044003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17646350 + ... + 17647547.

It is an arithmetic number, because the mean of its divisors is an integer number (5294084700).

Almost surely, 221141044303 is an apocalyptic number.

21141044303 is a deficient number, since it is larger than the sum of its proper divisors (35294497).

21141044303 is an equidigital number, since it uses as much as digits as its factorization.

21141044303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 35294496.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 21141044303 its reverse (30344014112), we get a palindrome (51485058415).

The spelling of 21141044303 in words is "twenty-one billion, one hundred forty-one million, forty-four thousand, three hundred three".

Divisors: 1 599 35293897 21141044303