2114112301131 has 4 divisors (see below), whose sum is σ = 2818816401512. Its totient is φ = 1409408200752.

The previous prime is 2114112301043. The next prime is 2114112301157. The reversal of 2114112301131 is 1311032114112.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 2114112301131 - 2¹¹ = 2114112299083 is a prime.

It is a super-2 number, since 2×2114112301131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2114112301098 and 2114112301107.

It is not an unprimeable number, because it can be changed into a prime (2114112401131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 352352050186 + ... + 352352050191.

It is an arithmetic number, because the mean of its divisors is an integer number (704704100378).

Almost surely, 2^{2114112301131} is an apocalyptic number.

2114112301131 is a deficient number, since it is larger than the sum of its proper divisors (704704100381).

2114112301131 is an equidigital number, since it uses as much as digits as its factorization.

2114112301131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 704704100380.

The product of its (nonzero) digits is 144, while the sum is 21.

Adding to 2114112301131 its reverse (1311032114112), we get a palindrome (3425144415243).

The spelling of 2114112301131 in words is "two trillion, one hundred fourteen billion, one hundred twelve million, three hundred one thousand, one hundred thirty-one".