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211412013031 = 355759435483
BaseRepresentation
bin1100010011100100100…
…0110100111111100111
3202012200200000000100201
43010321020310333213
511430432433404111
6241042113051331
721162662314012
oct3047110647747
9665620000321
10211412013031
118172862a52a
1234b81556b47
1316c22702ccb
14a3379a2379
15577529b6c1
hex3139234fe7

211412013031 has 4 divisors (see below), whose sum is σ = 211471452072. Its totient is φ = 211352573992.

The previous prime is 211412013013. The next prime is 211412013047. The reversal of 211412013031 is 130310214112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-211412013031 is a prime.

It is a super-2 number, since 2×2114120130312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (211412013011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29714185 + ... + 29721298.

It is an arithmetic number, because the mean of its divisors is an integer number (52867863018).

Almost surely, 2211412013031 is an apocalyptic number.

211412013031 is a deficient number, since it is larger than the sum of its proper divisors (59439041).

211412013031 is an equidigital number, since it uses as much as digits as its factorization.

211412013031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 59439040.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 211412013031 its reverse (130310214112), we get a palindrome (341722227143).

The spelling of 211412013031 in words is "two hundred eleven billion, four hundred twelve million, thirteen thousand, thirty-one".

Divisors: 1 3557 59435483 211412013031