211413343314113 has 4 divisors (see below), whose sum is σ = 214568766348720. Its totient is φ = 208257920279508.

The previous prime is 211413343314077. The next prime is 211413343314161. The reversal of 211413343314113 is 311413343314112.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 211413343314113 - 2¹⁶ = 211413343248577 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (211413343314013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1577711517203 + ... + 1577711517336.

It is an arithmetic number, because the mean of its divisors is an integer number (53642191587180).

Almost surely, 2^{211413343314113} is an apocalyptic number.

It is an amenable number.

211413343314113 is a deficient number, since it is larger than the sum of its proper divisors (3155423034607).

211413343314113 is an equidigital number, since it uses as much as digits as its factorization.

211413343314113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3155423034606.

The product of its digits is 31104, while the sum is 35.

Adding to 211413343314113 its reverse (311413343314112), we get a palindrome (522826686628225).

Subtracting 211413343314113 from its reverse (311413343314112), we obtain a palindrome (99999999999999).

The spelling of 211413343314113 in words is "two hundred eleven trillion, four hundred thirteen billion, three hundred forty-three million, three hundred fourteen thousand, one hundred thirteen".