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2114151142433 = 11209991565297
BaseRepresentation
bin11110110000111101001…
…110100101010000100001
321111002222211100201020012
4132300331032211100201
5234114240143024213
64255121100054305
7305512431130421
oct36607516452041
97432884321205
102114151142433
11745674227720
122a18a0b34395
13124495a91875
147447b0cc481
1539ed97534a8
hex1ec3d3a5421

2114151142433 has 8 divisors (see below), whose sum is σ = 2307445509600. Its totient is φ = 1921039910080.

The previous prime is 2114151142427. The next prime is 2114151142489. The reversal of 2114151142433 is 3342411514112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2114151142433 - 24 = 2114151142417 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2114151142433.

It is not an unprimeable number, because it can be changed into a prime (2114151142333) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 45759560 + ... + 45805737.

It is an arithmetic number, because the mean of its divisors is an integer number (288430688700).

Almost surely, 22114151142433 is an apocalyptic number.

It is an amenable number.

2114151142433 is a deficient number, since it is larger than the sum of its proper divisors (193294367167).

2114151142433 is a wasteful number, since it uses less digits than its factorization.

2114151142433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 91567407.

The product of its digits is 11520, while the sum is 32.

Adding to 2114151142433 its reverse (3342411514112), we get a palindrome (5456562656545).

The spelling of 2114151142433 in words is "two trillion, one hundred fourteen billion, one hundred fifty-one million, one hundred forty-two thousand, four hundred thirty-three".

Divisors: 1 11 2099 23089 91565297 1007218267 192195558403 2114151142433