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211424000133 = 370474666711
BaseRepresentation
bin1100010011100111011…
…0100011100010000101
3202012201111120000120110
43010321312203202011
511430444021001013
6241043222023233
721163166230563
oct3047166434205
9665644500513
10211424000133
1181734377625
1234b85577b19
1316c2503c178
14a339402a33
1557763682c3
hex3139da3885

211424000133 has 4 divisors (see below), whose sum is σ = 281898666848. Its totient is φ = 140949333420.

The previous prime is 211424000119. The next prime is 211424000143. The reversal of 211424000133 is 331000424112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 211424000133 - 216 = 211423934597 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (211424000143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35237333353 + ... + 35237333358.

It is an arithmetic number, because the mean of its divisors is an integer number (70474666712).

Almost surely, 2211424000133 is an apocalyptic number.

It is an amenable number.

211424000133 is a deficient number, since it is larger than the sum of its proper divisors (70474666715).

211424000133 is an equidigital number, since it uses as much as digits as its factorization.

211424000133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 70474666714.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 211424000133 its reverse (331000424112), we get a palindrome (542424424245).

The spelling of 211424000133 in words is "two hundred eleven billion, four hundred twenty-four million, one hundred thirty-three", and thus it is an aban number.

Divisors: 1 3 70474666711 211424000133