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2114310324121 = 16712660540863
BaseRepresentation
bin11110110001000110101…
…101110011111110011001
321111010101220212222110021
4132301012231303332121
5234120101420332441
64255144543550441
7305516403141112
oct36610655637631
97433356788407
102114310324121
11745746070236
122a19262bb421
131244bca56a08
14744942c7209
1539ee86e83d1
hex1ec46b73f99

2114310324121 has 4 divisors (see below), whose sum is σ = 2126970865152. Its totient is φ = 2101649783092.

The previous prime is 2114310324109. The next prime is 2114310324143. The reversal of 2114310324121 is 1214230134112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2114310324121 - 211 = 2114310322073 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2114310328121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6330270265 + ... + 6330270598.

It is an arithmetic number, because the mean of its divisors is an integer number (531742716288).

Almost surely, 22114310324121 is an apocalyptic number.

It is an amenable number.

2114310324121 is a deficient number, since it is larger than the sum of its proper divisors (12660541031).

2114310324121 is a wasteful number, since it uses less digits than its factorization.

2114310324121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12660541030.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 2114310324121 its reverse (1214230134112), we get a palindrome (3328540458233).

The spelling of 2114310324121 in words is "two trillion, one hundred fourteen billion, three hundred ten million, three hundred twenty-four thousand, one hundred twenty-one".

Divisors: 1 167 12660540863 2114310324121