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2114310544435 = 5422862108887
BaseRepresentation
bin11110110001000110101…
…110101001110000110011
321111010101221022011200001
4132301012232221300303
5234120101444410220
64255144552410431
7305516405046325
oct36610656516063
97433357264601
102114310544435
11745746200811
122a19263a6a17
131244bcb0308b
1474494343615
1539ee873d80a
hex1ec46ba9c33

2114310544435 has 4 divisors (see below), whose sum is σ = 2537172653328. Its totient is φ = 1691448435544.

The previous prime is 2114310544343. The next prime is 2114310544459. The reversal of 2114310544435 is 5344450134112.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2114310544435 - 211 = 2114310542387 is a prime.

It is a super-2 number, since 2×21143105444352 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2114310544394 and 2114310544403.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 211431054439 + ... + 211431054448.

It is an arithmetic number, because the mean of its divisors is an integer number (634293163332).

Almost surely, 22114310544435 is an apocalyptic number.

2114310544435 is a deficient number, since it is larger than the sum of its proper divisors (422862108893).

2114310544435 is an equidigital number, since it uses as much as digits as its factorization.

2114310544435 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 422862108892.

The product of its (nonzero) digits is 115200, while the sum is 37.

Adding to 2114310544435 its reverse (5344450134112), we get a palindrome (7458760678547).

The spelling of 2114310544435 in words is "two trillion, one hundred fourteen billion, three hundred ten million, five hundred forty-four thousand, four hundred thirty-five".

Divisors: 1 5 422862108887 2114310544435