Base | Representation |
---|---|
bin | 1100010011101001001… |
… | …0110011001110010001 |
3 | 202012202000111012100210 |
4 | 3010322102303032101 |
5 | 11431002414420213 |
6 | 241044044434333 |
7 | 21163316166504 |
oct | 3047222631621 |
9 | 665660435323 |
10 | 211431404433 |
11 | 81738574587 |
12 | 34b87b489a9 |
13 | 16c26732402 |
14 | a33a3ad13b |
15 | 5776d2c0c3 |
hex | 313a4b3391 |
211431404433 has 4 divisors (see below), whose sum is σ = 281908539248. Its totient is φ = 140954269620.
The previous prime is 211431404399. The next prime is 211431404447. The reversal of 211431404433 is 334404134112.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 211431404433 - 29 = 211431403921 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 211431404433.
It is not an unprimeable number, because it can be changed into a prime (211431404453) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35238567403 + ... + 35238567408.
It is an arithmetic number, because the mean of its divisors is an integer number (70477134812).
Almost surely, 2211431404433 is an apocalyptic number.
It is an amenable number.
211431404433 is a deficient number, since it is larger than the sum of its proper divisors (70477134815).
211431404433 is an equidigital number, since it uses as much as digits as its factorization.
211431404433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 70477134814.
The product of its (nonzero) digits is 13824, while the sum is 30.
Adding to 211431404433 its reverse (334404134112), we get a palindrome (545835538545).
The spelling of 211431404433 in words is "two hundred eleven billion, four hundred thirty-one million, four hundred four thousand, four hundred thirty-three".
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