211432234113 has 24 divisors (see below), whose sum is σ = 319109611392. Its totient is φ = 134644792128.

The previous prime is 211432234093. The next prime is 211432234127. The reversal of 211432234113 is 311432234112.

211432234113 is a `hidden beast` number, since 21 + 1 + 4 + 3 + 223 + 411 + 3 = 666.

211432234113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 211432234113 - 2⁵ = 211432234081 is a prime.

It is a super-3 number, since 3×211432234113³ (a number of 35 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (211432234313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 533556 + ... + 841157.

It is an arithmetic number, because the mean of its divisors is an integer number (13296233808).

Almost surely, 2^211432234113 is an apocalyptic number.

211432234113 is a gapful number since it is divisible by the number (23) formed by its first and last digit.

It is an amenable number.

211432234113 is a deficient number, since it is larger than the sum of its proper divisors (107677377279).

211432234113 is a wasteful number, since it uses less digits than its factorization.

211432234113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1375485 (or 1375482 counting only the distinct ones).

The product of its digits is 3456, while the sum is 27.

Adding to 211432234113 its reverse (311432234112), we get a palindrome (522864468225).

Subtracting 211432234113 from its reverse (311432234112), we obtain a palindrome (99999999999).

The spelling of 211432234113 in words is "two hundred eleven billion, four hundred thirty-two million, two hundred thirty-four thousand, one hundred thirteen".