Search a number
-
+
21143323143202 = 213813204736277
BaseRepresentation
bin1001100111010110100000…
…10000111110110000100010
32202212021121112122222100211
410303223100100332300202
510232403011211040302
6112545035241004334
74311361154262241
oct463532020766042
982767545588324
1021143323143202
116811918788807
1224558741836aa
13ba4a64767890
145314b13b4958
15269ebde43ad7
hex133ad043ec22

21143323143202 has 8 divisors (see below), whose sum is σ = 34154598923676. Its totient is φ = 9758456835312.

The previous prime is 21143323143193. The next prime is 21143323143263. The reversal of 21143323143202 is 20234132334112.

It can be written as a sum of positive squares in 2 ways, for example, as 20025526550121 + 1117796593081 = 4474989^2 + 1057259^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×211433231432022 (a number of 27 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 406602368113 + ... + 406602368164.

Almost surely, 221143323143202 is an apocalyptic number.

21143323143202 is a deficient number, since it is larger than the sum of its proper divisors (13011275780474).

21143323143202 is a wasteful number, since it uses less digits than its factorization.

21143323143202 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 813204736292.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 21143323143202 its reverse (20234132334112), we get a palindrome (41377455477314).

The spelling of 21143323143202 in words is "twenty-one trillion, one hundred forty-three billion, three hundred twenty-three million, one hundred forty-three thousand, two hundred two".

Divisors: 1 2 13 26 813204736277 1626409472554 10571661571601 21143323143202