Base | Representation |
---|---|
bin | 1100010011101100001… |
… | …1000001000101010001 |
3 | 202012202220021100202002 |
4 | 3010323003001011101 |
5 | 11431014133402423 |
6 | 241045215403345 |
7 | 21163531502051 |
oct | 3047303010521 |
9 | 665686240662 |
10 | 211444044113 |
11 | 817447179a5 |
12 | 34b90223555 |
13 | 16c29239603 |
14 | a33bd3d561 |
15 | 5777ec7228 |
hex | 313b0c1151 |
211444044113 has 4 divisors (see below), whose sum is σ = 211597154868. Its totient is φ = 211290933360.
The previous prime is 211444044089. The next prime is 211444044121. The reversal of 211444044113 is 311440444112.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 149040007249 + 62404036864 = 386057^2 + 249808^2 .
It is a cyclic number.
It is not a de Polignac number, because 211444044113 - 222 = 211439849809 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (211444044143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 76553306 + ... + 76556067.
It is an arithmetic number, because the mean of its divisors is an integer number (52899288717).
Almost surely, 2211444044113 is an apocalyptic number.
It is an amenable number.
211444044113 is a deficient number, since it is larger than the sum of its proper divisors (153110755).
211444044113 is a wasteful number, since it uses less digits than its factorization.
211444044113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 153110754.
The product of its (nonzero) digits is 6144, while the sum is 29.
Adding to 211444044113 its reverse (311440444112), we get a palindrome (522884488225).
The spelling of 211444044113 in words is "two hundred eleven billion, four hundred forty-four million, forty-four thousand, one hundred thirteen".
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