Base | Representation |
---|---|
bin | 11110110001010100100… |
… | …110010101001011100001 |
3 | 21111011000011011112110111 |
4 | 132301110212111023201 |
5 | 234121041032302001 |
6 | 4255224024131321 |
7 | 305525232004606 |
oct | 36612446251341 |
9 | 7434004145414 |
10 | 2114543244001 |
11 | 745855598401 |
12 | 2a1990306b41 |
13 | 124529099026 |
14 | 744b71d86ad |
15 | 3a00dda6851 |
hex | 1ec549952e1 |
2114543244001 has 4 divisors (see below), whose sum is σ = 2117150573104. Its totient is φ = 2111935914900.
The previous prime is 2114543243987. The next prime is 2114543244017. The reversal of 2114543244001 is 1004423454112.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2114543244001 - 233 = 2105953309409 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2114543284001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1303663335 + ... + 1303664956.
It is an arithmetic number, because the mean of its divisors is an integer number (529287643276).
Almost surely, 22114543244001 is an apocalyptic number.
It is an amenable number.
2114543244001 is a deficient number, since it is larger than the sum of its proper divisors (2607329103).
2114543244001 is an equidigital number, since it uses as much as digits as its factorization.
2114543244001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2607329102.
The product of its (nonzero) digits is 15360, while the sum is 31.
Adding to 2114543244001 its reverse (1004423454112), we get a palindrome (3118966698113).
The spelling of 2114543244001 in words is "two trillion, one hundred fourteen billion, five hundred forty-three million, two hundred forty-four thousand, one".
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