Base | Representation |
---|---|
bin | 1001100111100111010000… |
… | …00000110110110110101111 |
3 | 2202220010210221212000210211 |
4 | 10303303220000312312233 |
5 | 10233024413221114203 |
6 | 112553123204443251 |
7 | 4312126666136530 |
oct | 463635000666657 |
9 | 82803727760724 |
10 | 21152311504303 |
11 | 681571044a511 |
12 | 24575623a9527 |
13 | ba58679a1345 |
14 | 531ac503a687 |
15 | 26a3480c1c6d |
hex | 133ce8036daf |
21152311504303 has 4 divisors (see below), whose sum is σ = 24174070290640. Its totient is φ = 18130552717968.
The previous prime is 21152311504267. The next prime is 21152311504367. The reversal of 21152311504303 is 30340511325112.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 21152311504303 - 237 = 21014872550831 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21152311504903) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1510879393158 + ... + 1510879393171.
It is an arithmetic number, because the mean of its divisors is an integer number (6043517572660).
Almost surely, 221152311504303 is an apocalyptic number.
21152311504303 is a deficient number, since it is larger than the sum of its proper divisors (3021758786337).
21152311504303 is an equidigital number, since it uses as much as digits as its factorization.
21152311504303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3021758786336.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 21152311504303 its reverse (30340511325112), we get a palindrome (51492822829415).
The spelling of 21152311504303 in words is "twenty-one trillion, one hundred fifty-two billion, three hundred eleven million, five hundred four thousand, three hundred three".
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