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2115461300738 = 25333198336893
BaseRepresentation
bin11110110010001011010…
…100011100001000000010
321111020101010122122112212
4132302023110130020002
5234124431043110423
64255455101222122
7305560050240062
oct36621324341002
97436333578485
102115461300738
11746186832a85
122a1ba7861942
13124644345476
14745630d53a2
153a06479d578
hex1ec8b51c202

2115461300738 has 8 divisors (see below), whose sum is σ = 3173786977788. Its totient is φ = 1057532308144.

The previous prime is 2115461300737. The next prime is 2115461300741. The reversal of 2115461300738 is 8370031645112.

It can be written as a sum of positive squares in 2 ways, for example, as 1253139196969 + 862322103769 = 1119437^2 + 928613^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×21154613007382 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2115461300695 and 2115461300704.

It is not an unprimeable number, because it can be changed into a prime (2115461300737) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 99157781 + ... + 99179112.

Almost surely, 22115461300738 is an apocalyptic number.

2115461300738 is a deficient number, since it is larger than the sum of its proper divisors (1058325677050).

2115461300738 is a wasteful number, since it uses less digits than its factorization.

2115461300738 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 198342228.

The product of its (nonzero) digits is 120960, while the sum is 41.

The spelling of 2115461300738 in words is "two trillion, one hundred fifteen billion, four hundred sixty-one million, three hundred thousand, seven hundred thirty-eight".

Divisors: 1 2 5333 10666 198336893 396673786 1057730650369 2115461300738