Base | Representation |
---|---|
bin | 1001100111111010001111… |
… | …01000001001100010011011 |
3 | 2202221010010101210110021022 |
4 | 10303331013220021202123 |
5 | 10233211302411341210 |
6 | 113001530523033055 |
7 | 4312640421251132 |
oct | 463750750114233 |
9 | 82833111713238 |
10 | 21162505574555 |
11 | 6819a71767364 |
12 | 245952836b78b |
13 | ba680094aa87 |
14 | 5323b0c7a919 |
15 | 26a743017155 |
hex | 133f47a0989b |
21162505574555 has 4 divisors (see below), whose sum is σ = 25395006689472. Its totient is φ = 16930004459640.
The previous prime is 21162505574449. The next prime is 21162505574579. The reversal of 21162505574555 is 55547550526112.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 21162505574555 - 218 = 21162505312411 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 21162505574497 and 21162505574506.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2116250557451 + ... + 2116250557460.
It is an arithmetic number, because the mean of its divisors is an integer number (6348751672368).
Almost surely, 221162505574555 is an apocalyptic number.
21162505574555 is a deficient number, since it is larger than the sum of its proper divisors (4232501114917).
21162505574555 is an equidigital number, since it uses as much as digits as its factorization.
21162505574555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4232501114916.
The product of its (nonzero) digits is 10500000, while the sum is 53.
The spelling of 21162505574555 in words is "twenty-one trillion, one hundred sixty-two billion, five hundred five million, five hundred seventy-four thousand, five hundred fifty-five".
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