212002121301 has 4 divisors (see below), whose sum is σ = 282669495072. Its totient is φ = 141334747532.

The previous prime is 212002121299. The next prime is 212002121329. The reversal of 212002121301 is 103121200212.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 212002121301 - 2¹ = 212002121299 is a prime.

It is a super-3 number, since 3×212002121301³ (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (212002121381) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35333686881 + ... + 35333686886.

It is an arithmetic number, because the mean of its divisors is an integer number (70667373768).

Almost surely, 2^212002121301 is an apocalyptic number.

It is an amenable number.

212002121301 is a deficient number, since it is larger than the sum of its proper divisors (70667373771).

212002121301 is an equidigital number, since it uses as much as digits as its factorization.

212002121301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 70667373770.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 212002121301 its reverse (103121200212), we get a palindrome (315123321513).

The spelling of 212002121301 in words is "two hundred twelve billion, two million, one hundred twenty-one thousand, three hundred one".