Base | Representation |
---|---|
bin | 11110110110100000011… |
… | …011011001100100110011 |
3 | 21111200101010210002011210 |
4 | 132312200123121210303 |
5 | 234213441231223011 |
6 | 4301544300011203 |
7 | 306113212115403 |
oct | 36664033314463 |
9 | 7450333702153 |
10 | 2120110414131 |
11 | 74815206a756 |
12 | 2a2a84830b03 |
13 | 124c0559a438 |
14 | 74884738803 |
15 | 3a2379e36a6 |
hex | 1eda06d9933 |
2120110414131 has 32 divisors (see below), whose sum is σ = 2915940722688. Its totient is φ = 1369185482880.
The previous prime is 2120110414067. The next prime is 2120110414159. The reversal of 2120110414131 is 1314140110212.
It is not a de Polignac number, because 2120110414131 - 26 = 2120110414067 is a prime.
It is a super-2 number, since 2×21201104141312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2120110414098 and 2120110414107.
It is not an unprimeable number, because it can be changed into a prime (2120110414171) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 44887330 + ... + 44934536.
It is an arithmetic number, because the mean of its divisors is an integer number (91123147584).
Almost surely, 22120110414131 is an apocalyptic number.
2120110414131 is a deficient number, since it is larger than the sum of its proper divisors (795830308557).
2120110414131 is a wasteful number, since it uses less digits than its factorization.
2120110414131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 49011.
The product of its (nonzero) digits is 192, while the sum is 21.
Adding to 2120110414131 its reverse (1314140110212), we get a palindrome (3434250524343).
The spelling of 2120110414131 in words is "two trillion, one hundred twenty billion, one hundred ten million, four hundred fourteen thousand, one hundred thirty-one".
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