212012113 has 4 divisors (see below), whose sum is σ = 213537520. Its totient is φ = 210486708.

The previous prime is 212012077. The next prime is 212012123. The reversal of 212012113 is 311210212.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 212012113 - 2⁹ = 212011601 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 212012093 and 212012102.

It is not an unprimeable number, because it can be changed into a prime (212012123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 762495 + ... + 762772.

It is an arithmetic number, because the mean of its divisors is an integer number (53384380).

Almost surely, 2^212012113 is an apocalyptic number.

It is an amenable number.

212012113 is a deficient number, since it is larger than the sum of its proper divisors (1525407).

212012113 is a wasteful number, since it uses less digits than its factorization.

212012113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1525406.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 212012113 is about 14560.6357347473. The cubic root of 212012113 is about 596.2845519374.

Adding to 212012113 its reverse (311210212), we get a palindrome (523222325).

The spelling of 212012113 in words is "two hundred twelve million, twelve thousand, one hundred thirteen".