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212013123131 = 457463923683
BaseRepresentation
bin1100010101110011110…
…1111000011000111011
3202021020120002120101202
43011130331320120323
511433200324420011
6241221505004415
721213611545415
oct3053475703073
9667216076352
10212013123131
1181a06976437
123510a92370b
1316cba0c9c64
14a3937579b5
1557ace3823b
hex315cf7863b

212013123131 has 4 divisors (see below), whose sum is σ = 212477047272. Its totient is φ = 211549198992.

The previous prime is 212013123107. The next prime is 212013123137. The reversal of 212013123131 is 131321310212.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 212013123131 - 210 = 212013122107 is a prime.

It is a super-2 number, since 2×2120131231312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (212013123137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 231961385 + ... + 231962298.

It is an arithmetic number, because the mean of its divisors is an integer number (53119261818).

Almost surely, 2212013123131 is an apocalyptic number.

212013123131 is a deficient number, since it is larger than the sum of its proper divisors (463924141).

212013123131 is an equidigital number, since it uses as much as digits as its factorization.

212013123131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 463924140.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 212013123131 its reverse (131321310212), we get a palindrome (343334433343).

The spelling of 212013123131 in words is "two hundred twelve billion, thirteen million, one hundred twenty-three thousand, one hundred thirty-one".

Divisors: 1 457 463923683 212013123131