Search a number
-
+
212013312013 = 1091945076257
BaseRepresentation
bin1100010101110011111…
…0100110100000001101
3202021020120110011111101
43011130332212200031
511433200401441023
6241221513023101
721213613263166
oct3053476464015
9667216404441
10212013312013
1181a06a95338
123510a9b4a91
1316cba164c19
14a3937a676d
1557ace741ad
hex315cfa680d

212013312013 has 4 divisors (see below), whose sum is σ = 213958388380. Its totient is φ = 210068235648.

The previous prime is 212013311987. The next prime is 212013312067. The reversal of 212013312013 is 310213310212.

212013312013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 129943667529 + 82069644484 = 360477^2 + 286478^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-212013312013 is a prime.

It is a super-2 number, since 2×2120133120132 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (212013312613) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 972538020 + ... + 972538237.

It is an arithmetic number, because the mean of its divisors is an integer number (53489597095).

Almost surely, 2212013312013 is an apocalyptic number.

It is an amenable number.

212013312013 is a deficient number, since it is larger than the sum of its proper divisors (1945076367).

212013312013 is a wasteful number, since it uses less digits than its factorization.

212013312013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1945076366.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 212013312013 its reverse (310213310212), we get a palindrome (522226622225).

The spelling of 212013312013 in words is "two hundred twelve billion, thirteen million, three hundred twelve thousand, thirteen".

Divisors: 1 109 1945076257 212013312013